Knapsack Problem
Each item contains a weight and a value. A knapsack contains a finite capacity.
Goal: maximize the values in the knapsack while not overloading the capacity.
O/1 means we can either put items in the knapsack, or we do cannot. No splitting of items is allowed.
Base Conditions
0 weight = 0 items (cannot fit anything).
0 items = 0 knapsack items.
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