1 Multiples of 3 and 5

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.

#include <iostream>
#include <vector>
using namespace std;


//Multiples of 3 and 5
//Problem 1
int main()
{
    vector<int> sum3or5;

    for (int i = 1; i < 1000; i++)
    {
        if (i % 3 == 0 || i % 5 ==0)
        {
            sum3or5.push_back(i);
        }
    }

    int count = 0;

    for (int j = 0; j <= sum3or5.size(); j++)
    {
        count = count + sum3or5[j];
    }

    cout << count << endl;

    cin.get();
}

Solution: 233168