6 Sum Square Difference
The sum of the squares of the first ten natural numbers is,
12 + 22 + ... + 10^2 = 385 The square of the sum of the first ten natural numbers is,
(1 + 2 + ... + 10)^2 = 552 = 3025 Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.
Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.
#include <iostream>
#include <limits>
using namespace std;
void pause() { cin.ignore(numeric_limits<streamsize>::max(), '\n'); }
long int sumOfTheSquares()
{
long int currentSum = 0;
for (int i = 1; i <= 100; i++)
{
currentSum = currentSum + i*i;
}
return currentSum;
}
long long int squareOfTheSum()
{
long int currentSum = 0;
for (int i = 1; i <= 100; i++)
{
currentSum = currentSum + i;
}
long long int finalSum = currentSum*currentSum;
return finalSum;
}
int main()
{
long int a = squareOfTheSum();
long long int b = sumOfTheSquares();
cout << a - b;
pause();
}
Solution: 25164150
Last modified 3yr ago